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The equation of a line is $\frac{-3x}{5}$ + 3y = 6. Find the,

The equation of a line is
$\frac{-3x}{5}$ + 3y = 6. Find the,
(a) Gradient of the line.
(b) Equation of the line passing through the point (1,2) and perpendicular to the given line.

Answers

(a) Gradient of the line

-$\frac{3}{5}$ + 3y = 6 is

-3x + 15y = 30;

15y = 3x + 30

5y = x + 10;

y = $\frac{x}{5}$ + $\frac{10}{5}$

y = $\frac{x}{5}$ + 2; gradient is $\frac{1}{5}$

(b) Equation of the

perpendicular line through

(1,2) is

$m_2 = -5;$ $\frac{y-2}{x-1}$ = -5

y-2 = -5x + 5

y = -5x + 5 + 2,

y = -5x + 7

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johnmulu answered the question on June 13, 2017 at 11:15

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